Hi all,
I need manipulate AST of an expression in a macro, and pass same expression
in input to another macro, but I experience some problem.
I try to express my doubt with a simplified example:
macro tst2(e2::Expr)
println(e2.head)
end
macro tst(e1::Expr)
@tst2 esc(e1)
end
In previous code I want that call to @tst2 behave exact like call to @tst.
E.g. calling @tst2 in REPL I obtain:
julia> a = 2
julia> @tst2(a < 3)
comparison
but same call to @tst has no effect, and I cannot find an alternative
working form for @tst
Someone can help me to understand this odd behaviour of Julia's macro?
Many thanks in advance
Leonardo
