Hello everyone, I try to do $(x,y)=something, it says: syntax: invalid assignment location while +(x,y)=something is ok.
Is there any speciality of $ operator? Best, Cheng
Hello everyone, I try to do $(x,y)=something, it says: syntax: invalid assignment location while +(x,y)=something is ok.
Is there any speciality of $ operator? Best, Cheng