>
> type Foo{T<:AbstractFloat}
> x:: DenseArray{T}
> Foo() = new(call(T, 100))
> end
do you mean this?
在 2015年10月10日星期六 UTC+8下午9:36:39，cheng wang写道：
>
> I also want to use it to create a new type like the following (just
> example, not correct code):
> type Foo{F<:AbstractFloat, T<DenseArray}
> x::T{F}
> Foo() = new(call(T, F, 100))
> end
>
> The method you mentioned works for function, but it does not work for type.
>
> On Saturday, October 10, 2015 at 8:30:06 AM UTC+2, Tomas Lycken wrote:
>>
>> In the meantime, you can use
>>
>> foo{T<:AbstractFloat}(x::DenseArray{T})
>>
>> to get what you want.
>>
>> // T
>>
>>
