I see the variable a does not require interpolation, why does i require it?
eval evaluates expressions in a module’s global scope. a is defined in the
global scope, but i is local to the for loop and is undefined outside of
the loop.
— Mike
On Wednesday, 21 October 2015 11:18:34 UTC+2, 2n wrote:
>
> Thank you Mike, your solution works.
> However, I don't understand why the $ interpolation is required. I see the
> variable *a* does not require interpolation, why does *i* require it?
>
> On Wednesday, 21 October 2015 15:30:42 UTC+8, Michael Hatherly wrote:
>>
>> The try block is hiding an error, ERROR: UndefVarError: i not defined.
>> You need to interpolate the i variable in the quoted expression using $i:
>>
>> for i=1:4
>> try
>> if i==3 error() end
>> eval(:(push!(a,$i)))
>> catch e
>> end
>> end
>>
>> — Mike
>>
>> On Wednesday, 21 October 2015 09:11:44 UTC+2, 2n wrote:
>>>
>>> I'm trying to eval an expression in a try block and it doesn't seem to
>>> work.
>>> a=[]
>>> for i=1:4
>>> try
>>> if i==3 error() end
>>> eval(:(push!(a,i)))
>>> catch e
>>> end
>>> end
>>>
>>> a
>>>
>>> After running the above code a evaluates to:
>>>
>>> 0-element Array{Any,1}
>>>
>>> I'm expecting and want the same result as the code below which evaluates
>>> to:
>>> 3-element Array{Any,1}:
>>> 1
>>> 2
>>> 4
>>>
>>> a=[]
>>> for i=1:4
>>> try
>>> if i==3 error() end
>>> push!(a,i)
>>> catch e
>>> end
>>> end
>>>
>>> a
>>>
>>> Is there a way to get expression evalution to work in this case?
>>>
>>>
