Btw it is really cool to see julia running at 400% CPU when running a list 
comprehension.

I did some more benchmarks with larger N to reduce the noise a bit and the 
difference is actually not that great between Matlab and Julia. However, 
tying with Matlabs parallellized vectorized maps is great imho.

julia> @time h, f = Jakes_Flat( 926, 1e-6, 5000000, 0, 1, 0 )
  0.585940 seconds (153 allocations: 495.918 MB, 12.47% gc time)
(


>> tic; Jakes_Flat( 926, 1E-6, 5000000, 0, 1, 0 ); toc
Elapsed time is 0.609867 seconds.




On Wednesday, October 21, 2015 at 10:17:18 PM UTC+2, Kristoffer Carlsson 
wrote:
>
> For fun (and science) I tried out the new package 
> https://github.com/IntelLabs/ParallelAccelerator.jl for this problem.
>
> Here is the code:
>
> function Jakes_Flat( fd, Ts, Ns, t0 = 0, E0 = 1, phi_N = 0 )
> # Inputs:
> #
> # Outputs:
>   N0  = 8;                  # As suggested by Jakes
>   N   = 4*N0+2;             # An accurate approximation
>   wd  = 2*pi*fd;            # Maximum Doppler frequency
>   
>   ts   = collect(t0 + (0:Ns-1)*Ts)
>   tf  = ts[end] + Ts;
>   Ns = collect(1:N0)
>
>   coswt = [ cosvec(ts, wd)'; cosmat(ts, Ns, wd, N) ]
>   h = E0/sqrt(2*N0+1)*exp(im*[ phi_N pi/(N0+1)*(1:N0)']) * coswt
>   return h, tf;
> end
>
> @acc function cosvec(ts, wd)
>     Float64[sqrt(2)*cos(wd*t) for t in ts]
> end
>
> @acc function cosmat(ts, Ns, wd, N)
>     Float64[2*cos(wd*cos(2*pi/N*n)*t) for n in Ns, t in ts]
> end
>
>
> Benchmarking this I get:
>
> julia> @time Jakes_Flat( 926, 1e-6, 50000, 0, 1, 0 )
>   0.004779 seconds (115 allocations: 4.965 MB)
>
> and without calling the accelerated functions (by putting @noacc in front 
> of the function calls, I get):
>
> julia> @time Jakes_Flat_noacc( 926, 1e-6, 50000, 0, 1, 0 )
>   0.019072 seconds (75 allocations: 8.396 MB)
>
> The matlab code on my computer runs at:
>
> >> tic; Jakes_Flat( 926, 1E-6, 50000, 0, 1, 0 ); toc
> Elapsed time is 0.009936 seconds.
>
> So.. great victory for ParallelAccelerator.jl?
>
> On Sunday, October 18, 2015 at 1:17:50 PM UTC+2, Vishnu Raj wrote:
>>
>> Although Julia homepage shows using Julia over Matlab gains more in 
>> performance, my experience is quite opposite.
>> I was trying to simulate channel evolution using Jakes Model for wireless 
>> communication system.
>>
>> Matlab code is:
>> function [ h, tf ] = Jakes_Flat( fd, Ts, Ns, t0, E0, phi_N )
>> %JAKES_FLAT 
>> %   Inputs:
>> %       fd, Ts, Ns  : Doppler frequency, sampling time, number of samples
>> %       t0, E0      : initial time, channel power
>> %       phi_N       : initial phase of the maximum Doppler frequeny
>> %       sinusoid
>> %
>> %   Outputs:
>> %       h, tf       : complex fading vector, current time
>>
>>     if nargin < 6,  phi_N = 0;  end
>>     if nargin < 5,  E0 = 1;     end
>>     if nargin < 4,  t0 = 0;     end
>>     
>>     N0 = 8;         % As suggested by Jakes
>>     N  = 4*N0 + 2;  % an accurate approximation
>>     wd = 2*pi*fd;   % Maximum Doppler frequency[rad]
>>     t  = t0 + [0:Ns-1]*Ts;  % Time vector
>>     tf = t(end) + Ts;       % Final time
>>     coswt = [ sqrt(2)*cos(wd*t); 2*cos(wd*cos(2*pi/N*[1:N0]')*t) ];
>>     h  = E0/sqrt(2*N0+1)*exp(j*[phi_N pi/(N0+1)*[1:N0]])*coswt;
>> end
>> Enter code here...
>>
>> My call results in :
>> >> tic; Jakes_Flat( 926, 1E-6, 50000, 0, 1, 0 ); toc
>> Elapsed time is 0.008357 seconds.
>>
>>
>> My corresponding Julia code is
>> function Jakes_Flat( fd, Ts, Ns, t0 = 0, E0 = 1, phi_N = 0 )
>> # Inputs:
>> #
>> # Outputs:
>>   N0  = 8;                  # As suggested by Jakes
>>   N   = 4*N0+2;             # An accurate approximation
>>   wd  = 2*pi*fd;            # Maximum Doppler frequency
>>   t   = t0 + [0:Ns-1]*Ts;
>>   tf  = t[end] + Ts;
>>   coswt = [ sqrt(2)*cos(wd*t'); 2*cos(wd*cos(2*pi/N*[1:N0])*t') ]
>>   h = E0/sqrt(2*N0+1)*exp(im*[ phi_N pi/(N0+1)*[1:N0]']) * coswt
>>   return h, tf;
>> end
>> # Saved this as "jakes_model.jl"
>>
>>
>> My first call results in 
>> julia> include( "jakes_model.jl" )
>> Jakes_Flat (generic function with 4 methods)
>>
>> julia> @time Jakes_Flat( 926, 1e-6, 50000, 0, 1, 0 )
>> elapsed time: 0.65922234 seconds (61018916 bytes allocated)
>>
>> julia> @time Jakes_Flat( 926, 1e-6, 50000, 0, 1, 0 )
>> elapsed time: 0.042468906 seconds (17204712 bytes allocated, 63.06% gc 
>> time)
>>
>> For first execution, Julia is taking huge amount of time. On second call, 
>> even though Julia take considerably less(0.042468906 sec) than first(
>> 0.65922234 sec), it's still much higher to Matlab(0.008357 sec).
>> I'm using Matlab R2014b and Julia v0.3.10 on Mac OSX10.10.
>>
>> - vish
>>
>

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