Doing it with strings and parsing is not necessary (and will make all good Lispers very sad). You should splice and expression object into a function definition and eval instead:
julia> ex = :(2x + y) :(2x + y) julia> @eval f(x,y) = $ex f (generic function with 1 method) julia> f(3,4) 10 On Thu, Oct 22, 2015 at 1:38 PM, Alex Ames <alexander.m.a...@gmail.com> wrote: > There may be a slicker way to do this, but this should work: > > julia> fngen(expr,fn) = eval(parse(string(fn)* "=" * string(expr))) > fngen (generic function with 1 method) > > julia> expr = :(x + y) > :(x + y) > > julia> fngen(expr,:(f(x,y))) > func (generic function with 1 method) > > julia> f(2,2) > 4 > > On Thursday, October 22, 2015 at 11:10:09 AM UTC-5, Jānis Erdmanis wrote: >> >> I am implementing boundary element method with curved elements. As it is >> daunting task to evaluate derivatives I thought about using `Calculus` >> symbolic differentiation which as output gives expression. Now I need to >> convert this expression to a function, but how can I do it? >> >> As an example consider >> expr = :(x + y) >> how can I convert it to the function? >> function f(x,y) >> # Some magic here >> end >> >> >>
