I guess the simplest would be:
[Int[] for i = 1:3, j=1:3, k=1:3]
And to repeat what Milan already said, you don't want fill! because then
all your arrays point to the same memory location.
On Sunday, November 29, 2015 at 11:51:28 AM UTC+1, Aleksandr Mikheev wrote:
>
> Hi all. Once again I have some questions about Julia.
>
> I know that there is a possibility to create a list of arrays. For exmple:
>
> s = fill(Array(Int64,1),4)
>
> And then I can do something like this:
>
> s[1] = [1; 2]
> s[1] = [s[1]; 5]
>
> By parity of reasoning I did this:
>
> s = fill(Array(Int64,1),4,4,4)
>
> And it worked fine. But in both cases I had initial elements in s (like
> when I construct arrays with Array{Int64}(m,n)):
>
> julia> s = fill(Array(Int64,1),3,3,3)
> 3x3x3 Array{Array{Int64,1},3}:
> [:, :, 1] =
> [2221816832] [2221816832] [2221816832]
> [2221816832] [2221816832] [2221816832]
> [2221816832] [2221816832] [2221816832]
>
>
> [:, :, 2] =
> [2221816832] [2221816832] [2221816832]
> [2221816832] [2221816832] [2221816832]
> [2221816832] [2221816832] [2221816832]
>
>
> [:, :, 3] =
> [2221816832] [2221816832] [2221816832]
> [2221816832] [2221816832] [2221816832]
> [2221816832] [2221816832] [2221816832]
>
>
> Is there something I could do to prevent this? I know I could easily fix
> it by:
>
>
> for i = 1:3
> for j = 1:3
> for k = 1:3
> s[i,j,k] = []
> end
> end
> end
>
> But I guess this is a weird solution.
>
> Thank you in advance!
>
>
