Yes, you do need the .primary to make a maker. My mistake, I did not
notice the last part of your question.
julia> immutable Foo{D}
x::D
end
julia> onefoo=Foo(1)
Foo{Int64}(1)
julia> thePartYouWant(x) = typeof(x).name
thePartYouWant (generic function with 1 method)
julia> this = thePartYouWant(onefoo); this, typeof(this)
Foo, TypeName
On Tuesday, January 5, 2016 at 4:29:06 AM UTC-5, Sheehan Olver wrote:
>
> Thanks! you do need the .primary:
>
> *julia> **typeof(f).name(4.0)*
>
> *ERROR: MethodError: `call` has no method matching call(::TypeName,
> ::Float64)*
>
> Closest candidates are:
>
> BoundsError()
>
> BoundsError(*::Any...*)
>
> DivideError()
>
> ...
>
>
>
> *julia> **typeof(f).name.primary(4.0)*
>
> *Foo{Float64}(4.0)*
>
>
>
> On Monday, January 4, 2016 at 11:30:17 AM UTC, Jeffrey Sarnoff wrote:
>>
>> I meant: typeof(f).name
>>
>>
>> On Monday, January 4, 2016 at 6:27:43 AM UTC-5, Jeffrey Sarnoff wrote:
>>>
>>> try Foo.name (without the '.primary'), and as Mauro says (try not to use
>>> it much)
>>>
>>>
>>> On Monday, January 4, 2016 at 5:39:53 AM UTC-5, Mauro wrote:
>>>>
>>>> This should do the trick:
>>>>
>>>> Foo.name.primary
>>>>
>>>> (I think this defeats type inference, so try not to use it in
>>>> performance critical code)
>>>>
>>>> On Mon, 2016-01-04 at 11:31, Sheehan Olver <[email protected]> wrote:
>>>> > If I have a type
>>>> >
>>>> > ```julia
>>>> > immutable Foo{D}
>>>> > x::D
>>>> > end
>>>> >
>>>> > f=Foo(5)
>>>> > ```
>>>> >
>>>> >
>>>> > then `typeof(f)` gives me `Foo{Int}`. Is it possible to get access
>>>> to just
>>>> > `Foo`? I.e., I want to do:
>>>> >
>>>> > ```
>>>> > F=droptemplates(typeof(f)) # returns pointer to Foo
>>>> > F(1.0)
>>>> > ```
>>>>
>>>
