Hi, Suppose I want to fill the columns of a matrix which size I don't know beforehand:
A = zeros(3,0) for i=1:n A = [A [1,2,3]] end Is there a memory efficient way of doing that in Julia? I understand that the above syntax is allocating 3*i entries at iteration i which gives 3*(1+2+...+n) = 3*(n+1)n/2 allocations as opposed to 3n. -Júlio
