I'm not sure there's currently a way to get CPU time directly, although it's
just a couple ccalls so it wouldn't be hard to implement.
Out of curiosity, why do you want it? CPU time is often quite misleading; for
a multithreaded operation, it sums all the time used by all the cores.
Consequently, taking it at face value can lead you to think that your fast,
multithreaded calculation takes _longer_ than a slower single-threaded
implementation. I've encountered quite a few Matlab users who think repmat is
faster than bsxfun simply because the profiler told them that was true.
Following a dim memory, I see that I seem to have found this important enough
that I memorialized it in my startup.m file, for which the entire contents are:
if exist('distinguishable_colors','file')
set(0,'DefaultAxesColorOrder',distinguishable_colors(20));
end
% Put the profiler into a mode where it uses elapsed time rather than CPU
% time (which is messed up for multicore machines)
profile -timer real
Best,
--Tim
On Wednesday, February 03, 2016 12:28:28 PM Lytu wrote:
> Hello Julia users,
>
> Can someone tell me what's the equivalent of matlab elapsed cputime in Julia
>
> For example i Matlab, we can do this:
>
> t = cputime;
> x=4;
>
> iter = 1;
>
> z = ones(1,4);
>
> y=x*2*z;
>
> e = cputime-t
>
>
> But in Julia i don't seem to find how to do this. I thought i can use
>
> t=time()
>
> x=4;
>
> iter = 1;
>
> z = ones(1,4);
>
> y=x*2*z;
>
> e=time()-t
>
>
> But time() in Julia is not the elapsed CPU time, it's a wall clock time.
>
>
> Can someone help me?
>
>
> Thank you
