Hi,
I was wondering what is the best way going about the following issue.
Suppose I have a type with few outer constructors which I name differently,
and I want Julia to recognize these functions as constructors of that type.
For example
type SomeType <: SomeAbstract
name::ASCIIString
value::Int
end
TypeA(value::Int) = SomeType("A", value)
TypeB(value::Int) = SomeType("B", value)
In this case, I have two pseudo-types, TypeA and TypeB, which have the same
structure and are only different by their state. The problem with this
approach is that now TypeA and TypeB are functions and not datatypes, thus,
I cannot use operations defined on datetypes like checking for subtyping (TypeA
<: SomeAbstract), or overloading type construction using call.
Clearly, I could have defined two types which have exactly the same
structure but this seems wrong to me as it involes code replication.
Another possible solution is to define a macro which defines the type and
its outer constructor, and I would call the macro to define TypeA and
TypeB. Nonetheless, I was wondering if there was a way to tell Julia that
the functions TypeA and TypeB are in fact constructors of SomeType. I'd be
glag to hear about other solutions as well.
Uri
