did you mean to write 'i==2' instead of 'x==2' in the second if statement?
Am 08.02.2016 um 12:41 schrieb David van Leeuwen: > Hello, > > According > to > http://docs.julialang.org/en/release-0.4/manual/control-flow/#man-conditional-evaluation > variables > in if blocks do not introduce lexical scope, and hence are available > afterwards. This makes sense and is what I need. > > However, it seems afterwards relates to position in the encapsulating > block, and not to execution time. > > | > functiontestif() > | > for i in 1:2 > if i==1 > x = 0 > end > if x==2 > println(x) > end > end > end > > > This code gives me an undefined `x` in the print statement, where I > would have expected `x` to be initialized in the first iteration. It > seems I need to define `x` outside the for loop, even though I don't > need it there. > > Is this interpretation in Julia intentional? > > Cheers, > > ---david >
