Le mercredi 10 février 2016 à 14:12 -0800, Jeffrey Sarnoff a écrit :
> 
> I need a tuple -- it could have internal subtuples to organize
> subtypes of a subtype.
> 
> The use is to investigate more expressively elaborated and more
> flexibly organized alternatives to the current Numeric hierarchy.
> I would call allsubtypes(T) on some of my own Abstract types and then
> compare/contrast the sets of tuples yielded, and maybe reorganizing a
> few.
Sorry, I don't really get it. It's easy to transform the array that my
code returns into a tuple by doing (a...,), but I'm not sure what's the
point of using a tuple instead of an array.

Regards

> On Wednesday, February 10, 2016 at 4:12:42 AM UTC-5, Milan Bouchet-
> Valat wrote:
> > Le mercredi 10 février 2016 à 00:47 -0800, Jeffrey Sarnoff a
> > écrit : 
> > > I want to Typename{T,N} as Abstract
> > onlyif Typename.abstract==true, 
> > > otherwise Typename.abstract==false and I want to treat it as
> > Concrete 
> > > 
> > > Milan's solution displays the subtypes immediately. The way it is
> > set 
> > >  up is neat -- but how to pull the targeted type out of the
> > body? 
> > > 
> > > I need this to be a callable function that yields a manipulable
> > tuple 
> > > or vector or tuple of subtuples or  etc. 
> > Could you elaborate a bit? Do you need a tuple, or a tuple type? 
> > 
> > 
> > Regards 
> > 
> > 
> > 
> > > On Wednesday, February 10, 2016 at 3:26:14 AM UTC-5, Tommy
> > Hofmann 
> > > wrote: 
> > > > I think the recursive solution of Milan will give you a finite
> > list 
> > > > of all subtypes. But the list will contain things like Array{T,
> > N}, 
> > > > that is, a type with a parameter. How do you handle those? Do
> > you 
> > > > want to count them as abstract or concrete? 
> > > > 
> > > > On Wednesday, February 10, 2016 at 9:10:16 AM UTC+1, Jeffrey 
> > > > Sarnoff wrote: 
> > > > > Hello Tommy, 
> > > > > 
> > > > > OK, putting off inclusion of recursive types ... 
> > > > > and ignoring all possible values for the parameters of a 
> > > > > parameterized type unless already explicitly defined (present
> > in 
> > > > > memory) ... 
> > > > > 
> > > > >     allsupertypes(T) should be a short list from T to 
> > > > > supertype(T) to supertype(supertype(T)) .. to Any 
> > > > > 
> > > > >     allsubtypes(T) seems obtainable  
> > > > >     I can throw things into a tree until the leaves have no 
> > > > > subtypes, then traverse it; is there a nice way to do that 
> > > > > implicitly within a function? 
> > > > > 
> > > > >     
> > > > > 
> > > > > 
> > > > > On Wednesday, February 10, 2016 at 2:32:35 AM UTC-5, Tommy 
> > > > > Hofmann wrote: 
> > > > > > You implicitly assume that a type has only finitely many 
> > > > > > sub/supertypes, which for arbitrary types is clearly not
> > the 
> > > > > > case. The simplest example is Any but you can also get
> > this 
> > > > > > behavior when defining recursive types. More generally,
> > given 
> > > > > > types TL, TU there is no way of returning all types T with
> > TL 
> > > > > > <: T <: TU. You can describe this set using TypeVar, but
> > you 
> > > > > > cannot just write it down. 
> > > > > > 
> > > > > > Tommy 
> > > > > > 
> > > > > > On Wednesday, February 10, 2016 at 12:50:43 AM UTC+1,
> > Jeffrey 
> > > > > > Sarnoff wrote: 
> > > > > > > I see that your definition pours the subtypes from a
> > pitcher 
> > > > > > > of the poured subtypes.  The note about parametric types
> > is 
> > > > > > > well pointed. -- Jeffrey 
> > > > > > > 
> > > > > > > Clearly, the answer is therein.  Cloudily, I'm looking. 
> > > > > > > 
> > > > > > > 
> > > > > > > On Tuesday, February 9, 2016 at 3:43:48 PM UTC-5, Milan 
> > > > > > > Bouchet-Valat wrote: 
> > > > > > > > Le mardi 09 février 2016 à 12:24 -0800, Jeffrey Sarnoff
> > a 
> > > > > > > > écrit :  
> > > > > > > > > Any advice on quick 'n EZ coding of something like 
> > > > > > > > these?  
> > > > > > > > >  
> > > > > > > > > allsupertypes(Irrational) == ( Real, Number, Any )  
> > > > > > > > >  
> > > > > > > > > allsubtypes(Integer) == ( BigInt, Bool,  Signed, 
> > > > > > > > Int128,Int16,Int32,Int64,Int8, Unsigned, 
> > > > > > > > UInt128,UInt16,UInt32,UInt64,UInt8 )  
> > > > > > > > > abstractsubtypes(Integer) == ( Signed, Unsigned )  
> > > > > > > > > concretesubtypes(Integer) == ( 
> > > > > > > >
> > BigInt,Bool,UInt128,UInt16,UInt32,UInt64,UInt8,UInt16,UInt3 
> > > > > > > > 2,UInt64,UInt8)  
> > > > > > > > Here's a way to get all concretes ubtypes:  
> > > > > > > > subtypestree(x) = length(subtypes(x)) > 1 ? 
> > > > > > > > map(subtypestree, subtypes(x)) : x  
> > > > > > > > [subtypestree(AbstractArray)...;]  
> > > > > > > > 
> > > > > > > > You should be able to adapt this to return all
> > abstract 
> > > > > > > > types instead  
> > > > > > > > by using isleaftype() (which would better be called 
> > > > > > > > isconcretetype()?).  
> > > > > > > > But note there's the special case of parametric types, 
> > > > > > > > which aren't  
> > > > > > > > leaf types.  
> > > > > > > > 
> > > > > > > > 
> > > > > > > > Regards  

Reply via email to