An alternative is a comprehension:
[f(x) for (f,x) in zip(funs, vals)]
El lunes, 22 de febrero de 2016, 16:29:21 (UTC-5), Stefan Karpinski
escribió:
>
> Using a lambda works:
>
> julia> funs = [sin,cos,tan]
> 3-element Array{Function,1}:
> sin
> cos
> tan
>
> julia> vals = rand(3)
> 3-element Array{Float64,1}:
> 0.889165
> 0.64722
> 0.997409
>
> julia> map((f,x)->f(x), funs, vals)
> 3-element Array{Float64,1}:
> 0.776546
> 0.797763
> 1.54857
>
>
> On Mon, Feb 22, 2016 at 4:22 PM, Erik Schnetter <[email protected]
> <javascript:>> wrote:
>
>> I have an array of functions (`funs`) and an array of values (`vals`).
>> I want to apply the former to the latter, element-wise. When I write
>>
>> ```Julia
>> map(call, funs, vals)
>> ```
>> Julia replies with
>> ```
>> WARNING: call(f,args...) is deprecated, use f(args...) instead.
>> ```
>>
>> What is the correct syntax to use?
>>
>> -erik
>>
>> --
>> Erik Schnetter <[email protected] <javascript:>>
>> http://www.perimeterinstitute.ca/personal/eschnetter/
>>
>
>
