Thanks! This helped me with the problem at hand, but it would still be nice
to know if there's a more general way of doing this type of evaluation in
PyCall.
On Tuesday, March 15, 2016 at 12:23:55 PM UTC-4, Robin Deits wrote:
>
> This isn't pretty, but it might do the job:
>
> julia> np.mgrid[:__getitem__]((pybuiltin(:slice)(0,5),
> pybuiltin(:slice)(0,5)))
> 2x5x5 Array{Int64,3}:
> [:, :, 1] =
> 0 1 2 3 4
> 0 0 0 0 0
>
> [:, :, 2] =
> 0 1 2 3 4
> 1 1 1 1 1
>
> [:, :, 3] =
> 0 1 2 3 4
> 2 2 2 2 2
>
> [:, :, 4] =
> 0 1 2 3 4
> 3 3 3 3 3
>
> [:, :, 5] =
> 0 1 2 3 4
> 4 4 4 4 4
>
> It's just a deconstruction of the actual call that happens in python:
>
> In [7]: np.mgrid.__getitem__((slice(0,5), slice(0,5)))
> Out[7]:
> array([[[0, 0, 0, 0, 0],
> [1, 1, 1, 1, 1],
> [2, 2, 2, 2, 2],
> [3, 3, 3, 3, 3],
> [4, 4, 4, 4, 4]],
>
> [[0, 1, 2, 3, 4],
> [0, 1, 2, 3, 4],
> [0, 1, 2, 3, 4],
> [0, 1, 2, 3, 4],
> [0, 1, 2, 3, 4]]])
>
> On Tuesday, March 15, 2016 at 12:01:06 PM UTC-4, Chris wrote:
>>
>> I'm trying to use numpy's mgrid (
>> https://docs.scipy.org/doc/numpy-1.10.0/reference/generated/numpy.mgrid.html)
>>
>> via PyCall, but I can't figure out what the syntax should be. I've tried
>> every permutation I can think of, could someone help me out?
>>
>> The python call looks like:
>>
>> >>> np.mgrid[0:5,0:5]array([[[0, 0, 0, 0, 0], [1, 1, 1, 1, 1],
>> >>> [2, 2, 2, 2, 2], [3, 3, 3, 3, 3], [4, 4, 4, 4, 4]],
>> >>> [[0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4],
>> >>> [0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]])
>>
>>
>> Thanks in advance.
>>
>
