Thanks guys!
On Thursday, April 7, 2016 at 3:31:12 PM UTC+2, Matt Bauman wrote: > > I'd use logical indexing for this: > > a[isnan(a)] = 42 > clean_a = a[!isnan(a)] > > > On Thursday, April 7, 2016 at 9:20:05 AM UTC-4, Kristoffer Carlsson wrote: >> >> to replace with 42, maybe: >> >> map!((i) -> isnan(i)? 42 : i, a) >> >> to delete: >> >> deleteat!(a, find(isnan, a)) >> >> >> >> >> On Thursday, April 7, 2016 at 2:33:56 PM UTC+2, jw3126 wrote: >>> >>> I have an array, which has some NaNs and I want to do things like >>> replace them by 42 or delete them. What is the canonical way to do this? >>> >>
