Cedric fixed this recently in a PyCall update - do a Pkg.update() and that
should fix it.
On Monday, 16 May 2016 10:27:48 UTC+1, Henri Girard wrote:
>
> Hi,
> If I use this plot in terminal julia it works fine, but in IJulia it does
> an error.
> Any help
> Thanks
> HG
>
> using Plots
> pyplot(reuse=true)
> x=y=linspace(-5,5,30)
> surface(x,y,(x,y)->sin(x)+cos(y),
> line=(1,:black),fill=(0.8,:rainbow),
> tickfont=font(8),guidefont=font(6),
> title="graphe",xlab="X",ylab="Y",
> size=(400,300))
>
>
> PyError (:PyObject_Call) <type 'exceptions.IOError'>
> IOError('Julia exception: MethodError(flush,(IOBuffer(data=UInt8[...],
> readable=true, writable=true, seekable=true, append=false, size=225292,
> maxsize=Inf, ptr=225293, mark=-1),))',)
> File "/usr/lib/python2.7/dist-packages/matplotlib/backend_bases.py", line
> 2232, in print_figure
> **kwargs)
> File "/usr/lib/python2.7/dist-packages/matplotlib/backends/backend_svg.py",
> line 1206, in print_svg
> return self._print_svg(filename, svgwriter, fh_to_close, **kwargs)
> File "/usr/lib/python2.7/dist-packages/matplotlib/backends/backend_svg.py",
> line 1235, in _print_svg
> renderer.finalize()
> File "/usr/lib/python2.7/dist-packages/matplotlib/backends/backend_svg.py",
> line 295, in finalize
> self.writer.flush()
> File "PyCall.jl", line 1, in <lambda>
>
>
>
