The two functions test4 and test5 below are equivalent, but test5 is much
faster than test4. Apparently test4 is carrying out a heap allocation on
each iteration of the j-loop. Why? In general, which kinds of assignment
statements of the form <array>=<array> create temporaries, and which don't?
(In the example below, if the indirect addressing via array i is
eliminated, then the two functions have comparable performance.)
Thanks,
Steve Vavasis
function test4(n)
y = [2.0, 6.0, 3.0]
i = [1, 2, 3]
z = [0.0, 0.0, 0.0]
u = 0.0
for j = 1 : n
z[:] = y[i]
u += sum(z)
end
u
end
function test5(n)
y = [2.0, 6.0, 3.0]
i = [1, 2, 3]
z = [0.0, 0.0, 0.0]
u = 0.0
for j = 1 : n
for k = 1 : 3
z[k] = y[i[k]]
end
u += sum(z)
end
u
end
julia> @time Testmv.test4(10000000)
1.071396 seconds (20.00 M allocations: 1.192 GB, 7.03% gc time)
1.1e8
julia> @time Testmv.test5(10000000)
0.184411 seconds (4.61 k allocations: 198.072 KB)
1.1e8