On Thursday, July 21, 2016 at 11:35:56 AM UTC-4, Chris Rackauckas wrote: > > I don't think you can do > > x[:] =x .+deltax > > as fancy syntax here since the x is part of the statement though (you can > check). >
No, that will allocate a new array to store x .+ deltax, and then store that new array in-place in x. (In 0.6, the plan is for "x .= x .+ deltax" or "x .+= deltax" to be entirely in-place, but that is still work in progress.)
