that could be handy indeed, thanks.
I would also like to automatize the process using
```julia
mlist = methodswith(A, ModA)
```
but looks like objects of type Method are not callable
```julia
julia> mlist[1](1)
ERROR: MethodError: objects of type Method are not callable
in eval_user_input(::Any, ::Base.REPL.REPLBackend) at ./REPL.jl:64
in macro expansion at ./REPL.jl:95 [inlined]
in (::Base.REPL.##3#4{Base.REPL.REPLBackend})() at ./event.jl:68
```
How do I go from a Method object to the corresponing callable Function
object?
Il giorno lun 26 set 2016 alle ore 16:39 Mauro <[email protected]> ha
scritto:
> This macro might work for you
>
> https://github.com/JuliaLang/DataStructures.jl/blob/8422ca9f66bfaa0f257b2bbbc8637c844d49ea68/src/delegate.jl
>
> On Mon, 2016-09-26 at 16:31, Carlo Lucibello <[email protected]>
> wrote:
> > Hi everybody,
> > I'm looking for a metaprogramming trick to solve the following problem
> (I'm
> > confident it can be done efficiently with julia) . Let's say I have
> defined a
> > type in a module along with some methods:
> > module ModA
> > export A,f1,f2,f3
> >
> > type A
> > ...
> > end
> >
> > f1(a::A, x::Int) = ...
> > f2(x, a::A, y) = ...
> > f3(a1::A,a2::A) = ...
> >
> > end #module
> > Now I have a second type that encapsulate the first
> >
> > using ModA
> >
> > type B
> > a::A
> > ...
> > end
> >
> > and I would like to define a macro that automatically defines all the
> exported
> > function in ModA for the type B in the trivial way, that is
> >
> > f1(b::B, x::Int) = f1(b.a, x)
> > f2(x, b::B, y) = f1(x, b.a, y)
> > f3(b1::B, b2::B) = f1(b1.a, b2.a)
> >
> > A starting point could be methodswith(A, ModA), but I don't know how to
> procede
> > further. Suggestions?
> >
> > Bye,
> > Carlo
>
