BIG THX, but what about Float array ?
julia> Int.(rand(Bool,10))
10-element Array{Int64,1}:
1
0
1
1
1
0
1
0
0
0
julia> Int.(rand(10))
ERROR: InexactError()
in macro expansion at .\broadcast.jl:129 [inlined]
in macro expansion at .\simdloop.jl:73 [inlined]
in macro expansion at .\broadcast.jl:123 [inlined]
in _broadcast!(::Type{Int64}, ::Array{Int64,1}, ::Tuple{Tuple{Bool}},
::Tuple{Tuple{Int64}}, ::Tuple
::Type{Val{1}}) at .\broadcast.jl:117
in broadcast!(::Type{T}, ::Array{Int64,1}, ::Array{Float64,1}) at
.\broadcast.jl:172
in broadcast_t(::Type{T}, ::Type{T}, ::Array{Float64,1},
::Vararg{Array{Float64,1},N}) at .\broadcas
in broadcast(::Type{T}, ::Array{Float64,1}) at .\broadcast.jl:230
W dniu czwartek, 27 października 2016 10:00:42 UTC+2 użytkownik Ángel de
Vicente napisał:
>
> Hi,
>
> [email protected] <javascript:> writes:
>
> > in ver 0.5 how to convert to Int f.e bool or Float
> >
> > julia> int(rand(Bool,10))
> > ERROR: UndefVarError: int not defined
> >
> > julia> convert(Int64,rand(Bool,10))
> > ERROR: MethodError: Cannot `convert` an object of type Array{Bool,1} to
> an
> > object of type Int64
> > This may have arisen from a call to the constructor Int64(...),
> > since type constructors fall back to convert methods.
> >
>
> just learning Julia, so probably there are better ways, but this works:
>
> ,----
> | julia> VERSION
> | v"0.5.0"
> |
> | julia> Int(rand(Bool))
> | 1
> |
> | julia> [Int(x) for x in rand(Bool,5)]
> | 5-element Array{Int64,1}:
> | 0
> | 1
> | 0
> | 1
> | 0
> |
> | julia>
> `----
>
> --
> Ángel de Vicente
> http://www.iac.es/galeria/angelv/
>
