One way you could do this would be to write and commit a policy that matches
the conditions you want and accepts them, then discards everything else. Then,
use the 'test policy' command to display the output.
user@router> test policy foo 0/0
inet.0: 2 destinations, 2 routes (2 active, 0 holddown, 0 hidden)
+ = Active Route, - = Last Active, * = Both
10.210.58.0/26 *[Direct/0] 1w1d 01:48:38
> via ge-2/0/0.0
Policy foo: 1 prefix accepted, 1 prefix rejected
Note that the first argument to 'test policy' is the name of the policy to
test. The second argument is the range of active prefixes in your local routing
table which should be used as input to the routing policy. By using 0/0, your
evaluating the policy against all active IPv4 routes in your routing table.
Only routes that are accept by the policy will be displayed in the output.
Note, use 'test policy foo ::/0' to evaluate the policy against active IPv6
prefixes in inet6.0.
--Stacy
On May 5, 2011, at 3:51 PM, Bill Blackford wrote:
> I want to be able to search the route table for prefixes announced
> from a certain peer and of a range of lengths. ex, give me all routes
> announced from and through HE but filter by 'upto' /19.
>
> so,
>
> show route aspath-regex .*6939.* terse <upto /19>
>
> or,
>
> show route receive-protocol bgp ###.###.###.### aspath-regex .*6939.*
> terse <upto /19>
>
> Is there way to do this?
>
> The best I've come up with is 'sh route aspath-regex .*6939.* | except
> /2' This is obviously not a very flexible approach.
>
> Thank you,
>
> -b
>
>
> --
> Bill Blackford
> Network Engineer
>
> Logged into reality and abusing my sudo privileges.....
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