One way that you can sometimes get round this is to define a function in
Python first, and then call it from JS, rather than setting a variable from
JS.

On 3 August 2016 at 18:57, Matthias Bussonnier <[email protected]
> wrote:

> These is no way to go around that, the messages and execution requests
> are queued as the ZMQ layer.
> So you submit cell 2 before `kernel.execute(command) ;` to be back on the
> bage.
>
> So execute all will always have this behavior.
>
> --
> M
>
> On Wed, Aug 3, 2016 at 10:38 AM, marq h <[email protected]> wrote:
> > Hi Jupyter folks
> >
> > I am puzzled by the behaviour in this case:
> >
> > Cell 1
> > import IPython
> > javascript = """
> >     var url = window.location;
> >
> >         var command = "url" + " = '" + url + "'";
> >
> >         var kernel = IPython.notebook.kernel;
> >
> >
> >         kernel.execute(command) ;
> > """
> > IPython.display.display(IPython.display.Javascript(javascript))
> >
> >
> >
> > Cell 2
> > print(url)
> >
> >
> > If I run cell 1, then run cell 2, by hand, one after the other, then all
> is
> > fine: the url is printed.  If i 'run all' then the "name 'url' is not
> > defined" (this is the case if i rerun cell 2, after having run all)
> >
> > It's like that kernel.execute is being trampled on by the print and the
> url
> > variable is never properly assigned.
> >
> > I've tried time.sleep and other work around steps but to no avail, if i
> run
> > all, then the kernel.execute doesn't make a result.  Any python code
> > following cell 1 seems to trigger this problem
> >
> > any advice on how to deal with this would be very gratefully received
> > cheers
> > mark
> >
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