Hi Jianwu,
You would need to protect the backslash with a backslash.
Try replaceAll("a", "\\"")
I'm not sure if that will work.
In general, backslashes are somewhat evil.
For example: Is the string "\bc" three characters: backslash, b and c
or two characters: backspace and c?
I'm not sure what replaceAll method you are calling here, I'm guessing
you are invoking that method on a String?
A small test model would help.
I'm not confident that backslashes work well in the expression lange.
_Christopher
On 5/3/13 3:16 PM, Jianwu Wang wrote:
Hi Christopher,
I'm using "Expression Evaluator" trying to replace some strings to
backslash, such as from "abc" to "\bc". Command like
replaceAll("a","\") always has error: Found unterminated string :
"\"). Similar attempts also failed.
I searched Kepler/Ptolemy documents and mailing lists and didn't
find answer. Would you please help me out? Thanks.
--
Christopher Brooks, PMP University of California
Academic Program Manager & Software Engineer US Mail: 337 Cory Hall
CHESS/iCyPhy/Ptolemy/TerraSwarm Berkeley, CA 94720-1774
c...@eecs.berkeley.edu, 707.332.0670 (Office: 545Q Cory)
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