On Tue, 2009-10-13 at 15:42 -0400, [email protected] wrote: > Basically what I'm trying to do in > my DK function is: "encrypt my 'kerberos' block with the temporary key > I got from my derive bytes function." > > Am I understanding how I create the final key correctly here?
You have the right idea to the best of my understanding, with the proviso that you should be using the cipher's default input vector (which I believe is all-bits-zero) and not an IV left over from any previous encryption. So, I'm not immediately sure why you're not getting the right result. ________________________________________________ Kerberos mailing list [email protected] https://mailman.mit.edu/mailman/listinfo/kerberos
