Hello everybody,

I am tracing the boot kernel process 
(http://tldp.org/HOWTO/Linux-i386-Boot-Code-HOWTO) and I have a 
question: GNU/GRUB loads vmlinuz at 0x7c00 memory, does not it? And 
then, the first instruction CPU executes is in bootsec.S, does not it? 
Have I understood well?

I do not if this is the place for this question.

Regards,
Román.

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