Sorry, silly question, but did you try as root? kexec load tries to put the knew kernel on memory and after that tries a syscall to kexec_load to finish with a kexec_reboot, since it handles with mem and syscalls maybe just as a root you will run it properly
Also have that [email protected] list. []'s On Thu, Oct 3, 2013 at 10:05 AM, Dmitry Kolesov <[email protected]> wrote: > Hello. > > Could anybody help with kexec. I cannot find some informaton from google. > I try to use kexec for fast boot new kernel but I have error below: > > # kexec -l /boot/vmlinuz-3.12.0-rc1+ > --initrd=/boot/initramfs-3.12.0-rc1+.img --command-line="$(cat > /proc/cmdline)" > kexec_load failed: Operation not permitted > entry = 0x24eff5790 flags = 3e0000 > nr_segments = 3 > segment[0].buf = 0x7fd169783210 > segment[0].bufsz = 505250 > segment[0].mem = 0x24d000000 > segment[0].memsz = 1413000 > segment[1].buf = 0xbc3770 > segment[1].bufsz = 4310 > segment[1].mem = 0x24efef000 > segment[1].memsz = 5000 > segment[2].buf = 0xbba650 > segment[2].bufsz = 90e0 > segment[2].mem = 0x24eff5000 > segment[2].memsz = b000 > > KEXEC option in the config is enabled. > > How can I decid this problem? > > Regards, > Dmitry > > _______________________________________________ > Kernelnewbies mailing list > [email protected] > http://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies > > -- ---------------------------------------------- Leônidas S. Barbosa (Kirotawa)
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