> As far as I understood Dan Carpenters (last) post in that thread, the content > in the buffer > is already in little endian order. In this case the code is correct as it is > and there is no need > for the change you propose.
Yes, I believe Mr. Carpenter is mistaken - I think the data is in host-endian order. Please see my analysis of where that buffer's contents are filled. Can you comment on whether my analysis is correct or not? Regards, Perry _______________________________________________ Kernelnewbies mailing list [email protected] https://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies
