El Wed, Jul 02, 2008 at 06:38:52PM +0530 Rajat Jain ha dit:
> Although kmalloc() gives you 24 bytes per call that you can use,
> but internally it allocates in pages, and hence 1 page (=4K bytes in each
> iteration)
though kmalloc() usually wastes some memory in allocations it doesn't
waste an entire page in order to satisfy a request of 24
bytes. kmalloc is based on the slab layer, in the best case a chunk of
32 bytes will be returned from the corresponding slab cache.
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Matthias Kaehlcke
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Barcelona
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