On Wed, Aug 6, 2008 at 7:08 AM, Bradley Hanna <[EMAIL PROTECTED]> wrote: > I need to clarify my understanding of how the 2.6 runqueue is managed. > > The datastructure is made up of 140 lists each able to contain an infinite > number of processes. When a process with priority of 100 is created for > example it is added to the list of processes with priority of 100.
in its active list, if I may add.... then after it runs and exhaust its time slice it will go to expired list (in the new priority list IIRC). > It is > added to the end of the list therefore for each list in the runqueue the > processes are selected in fifo order. So, the 10th process of priority 100 > isn't evaluated until the first nine are evaluated. correct. regards, Mulyadi. -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to [EMAIL PROTECTED] Please read the FAQ at http://kernelnewbies.org/FAQ
