> Hm,from the function's comment:
> 
> /*
>  *This callback runs from the timer interrupt, and checks
> * whether the watchdog thread has hung or not:
>  */
> 
> that means,it runs in interrupt context, thus AFAIK it won't 
> be preempted.
Thanks Mulyadi.

If I wanted to trace back through the code that got to softlock_tick(),
ehat would I look for to find out if pre-emtive switching had been
disabled in the kernel source that I have


Adrian

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