Am Donnerstag 27 August 2009 00:18:28 schrieb Stoyan Gaydarov:
> I wanted to know what memcpy returned as a result, and if it
> needs/should be checked. There are several places in the kernel where i
> noticed it being used but i also saw a warning about the result not
> being used, so i wanted to know a little more about it.
>
> -Stoyan
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Hi,
*memcpy is defined in .../lib/string.c (+ some macros etc - use cscope to
find more references) as
/**
* memcpy - Copy one area of memory to another
* @dest: Where to copy to
* @src: Where to copy from
* @count: The size of the area.
*
* You should not use this function to access IO space, use memcpy_toio()
* or memcpy_fromio() instead.
*/
void *memcpy(void *dest, const void *src, size_t count)
{
char *tmp = dest;
const char *s = src;
while (count--)
*tmp++ = *s++;
return dest;
}
You can see it just returns the destination address that you have passed to it
-> so I guess unless it is possible that you have already passed it a null
pointer (which might horribly fail) it is not really necessary to check the
result.
Peter
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