Indeed. a b !(!a || !b) a && b 0 0 0 0 0 1 0 0 1 0 0 0 1 1 1 1
Please be careful. I'm guessing that this patch was untested. On Tue, Apr 12, 2016 at 04:23:18PM -0500, José Ignacio wrote: > I don't believe that's correct !(!a || !b) is equal to a && b (de > morgan) > http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/ietron/demorgan2.gif > > On Tue, Apr 12, 2016 at 4:16 PM, Pereira, Patrick > <patrick.pere...@intel.com> wrote: > > Hi, > > > > Corrections to avoid unnecessary boolean operations > > !(!a || !b) = a || b > > > > Best Regards, > > _______________________________________________ > > Mailing list: https://launchpad.net/~kicad-developers > > Post to : kicad-developers@lists.launchpad.net > > Unsubscribe : https://launchpad.net/~kicad-developers > > More help : https://help.launchpad.net/ListHelp > > > > _______________________________________________ > Mailing list: https://launchpad.net/~kicad-developers > Post to : kicad-developers@lists.launchpad.net > Unsubscribe : https://launchpad.net/~kicad-developers > More help : https://help.launchpad.net/ListHelp _______________________________________________ Mailing list: https://launchpad.net/~kicad-developers Post to : kicad-developers@lists.launchpad.net Unsubscribe : https://launchpad.net/~kicad-developers More help : https://help.launchpad.net/ListHelp