Hi Rogan,
I reintroduced two filters date abd itemtype. So that i can sekect any date be
it weekly monthly or quarterly etc. I also have different itemtypes sone of
which do not start wih a digit and I need to filter them out yo get accurate
results. (Your advice on whether the filters might be sn issue is verywelcome)
Below is my query.
SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS",
count(statistics.type) AS 'NUMBER'
FROM borrowers
LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber)
LEFT JOIN items ON (items.itemnumber = statistics.itemnumber)
LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber =
items.biblioitemnumber)
WHERE statistics.type IN ('issue', 'renew')
AND date(datetime) BETWEEN <<Date BETWEEN (yyyy-mm-dd)|date>> AND <<and
(yyyy-mm-dd)|date>>
AND items.itype = <<Item type|itemtypes>>
GROUP BY SUBSTRING(itemcallnumber,1,1)
UNION ALL
SELECT "TOTAL" AS "CLASS", SUM(statistics.type) AS 'NUMBER'
FROM borrowers
LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber)
LEFT JOIN items ON (items.itemnumber = statistics.itemnumber)
LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber =
items.biblioitemnumber)
WHERE statistics.type IN ('issue', 'renew')
Sent from my Samsung Galaxy smartphone.-------- Original message --------From:
[email protected] Date: 15/03/2020 00:48 (GMT+03:00) To: muiru james
<[email protected]>, Koha <[email protected]> Subject: Re: [KOHA] SQL
CIRCULATION REPORT- how to SUM
Hi James,
The query I posted worked with my quick test. Could you post your query as it
is now?
On Sat, Mar 14, 2020 at 9:52 AM muiru james <[email protected]> wrote:
Hi Rogan and All,
I cant thank you enough for the tremendous effort you have put towards helping
me solve my problem.
You do indeed understand well what I need.
The UNION ALL is working well by adding a new row below the last class group.
However the SUM function is returning a 0 (zero). It seems its not adding up
the numbers.
Please dont give up but help me find out the last remaining bit. We are almost
there.
Most appreciated
James
On Thu, Mar 12, 2020 at 2:57 PM <[email protected]> wrote:
Hi James,
If I'm understanding correctly you want an additional row giving a sum of all
the numbers in addition to the per class one? The simplest way it occurs to
me to do that is with a UNION ALL statement. I've taken some filters out for
brevity but this illustrates the approach:
SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS",
count(statistics.type) AS 'NUMBER'
FROM borrowers
LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber)
LEFT JOIN items ON (items.itemnumber = statistics.itemnumber)
LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber =
items.biblioitemnumber)
WHERE statistics.type IN ('issue', 'renew')
GROUP BY SUBSTRING(itemcallnumber,1,1)
UNION ALL
SELECT "All Classes" AS "CLASS", SUM(statistics.type) AS 'NUMBER'
FROM borrowers
LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber)
LEFT JOIN items ON (items.itemnumber = statistics.itemnumber)
LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber =
items.biblioitemnumber)
WHERE statistics.type IN ('issue', 'renew')
Basically with UNION ALL you can create other queries that don't have to be
tied to the data of the previous queries so long as the columns line up.
On Thu, Mar 12, 2020 at 3:04 AM muiru james <[email protected]> wrote:
Hi Rogan and Team,
I really appreciate your assistance towards my problem. The query does indeed
work to answer my need. Another query was also pushed to me towards the same.
I'm now looking for a way to SUM my answer to get the total number of books
issued. Any suggestions would be most welcome for any of the 2 queries. The
other SQL query is as below: -
SELECT CONCAT(SUBSTRING(itemcallnumber,1,1), '00') AS "CLASS",
count(statistics.type) AS 'NUMBER'
FROM borrowers
LEFT JOIN statistics ON (statistics.borrowernumber=borrowers.borrowernumber)
LEFT JOIN items ON (items.itemnumber = statistics.itemnumber)
LEFT JOIN biblioitems ON (biblioitems.biblioitemnumber =
items.biblioitemnumber)
WHERE statistics.type IN ('issue', 'renew')
AND date(statistics.datetime) BETWEEN <<Date BETWEEN (yyyy-mm-dd)|date>> AND
<<and (yyyy-mm-dd)|date>>
AND statistics.itemtype = 'BK'
GROUP BY SUBSTRING(itemcallnumber,1,1)
ORDER BY items.itemcallnumber ASC
N.B My desire is to SUM the NUMBER column as TOTAL.
Please assist team
Warm Regards. JAMES
On Fri, Mar 6, 2020 at 7:10 PM <[email protected]> wrote:
Hi James,
One simple way to handle it is with a case statement. The following example
has a static between filter for the dates but it illustrates this approach. You
can also do some cleaning to make sure there aren't spaces in front and it
assumes that all of your DDC numbers in fact start with a digit.
SELECT
COUNT(*),
CASE
WHEN LEFT(it.itemcallnumber,1) = '0' THEN '000s'
WHEN LEFT(it.itemcallnumber,1) = '1' THEN '100s'
WHEN LEFT(it.itemcallnumber,1) = '2' THEN '200s'
WHEN LEFT(it.itemcallnumber,1) = '3' THEN '300s'
WHEN LEFT(it.itemcallnumber,1) = '4' THEN '400s'
WHEN LEFT(it.itemcallnumber,1) = '5' THEN '500s'
WHEN LEFT(it.itemcallnumber,1) = '6' THEN '600s'
WHEN LEFT(it.itemcallnumber,1) = '7' THEN '700s'
WHEN LEFT(it.itemcallnumber,1) = '8' THEN '800s'
WHEN LEFT(it.itemcallnumber,1) = '9' THEN '900s'
ELSE 'OTHER'
END
from (SELECT * FROM issues UNION ALL SELECT * FROM old_issues) i
JOIN items it ON it.itemnumber = i.itemnumber
WHERE DATE(i.timestamp) BETWEEN '2020-02-01' AND '2020-02-29'
GROUP BY 2 ORDER BY 2;
On Thu, Mar 5, 2020 at 11:06 AM muiru james <[email protected]> wrote:
Dear All,
My library uses DDC scheme of classification and we are looking for a
report that will count items checked out allowing us to select day(s) of
issue, select itemtype and group the statistics by DDC 10 broad classes.
*EXAMPLE*
IN a date range say 1st-31st March 2020.
*DDC Class | NO. of books issued*
000 - 12
100 - 26
200 - 157
.
.
.
900 - 230
The report can generate statistics for a day, month, quarter, e.t.c.
Any assistance however close will be greatly appreciated.
Thank you as you prepare to help
James
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