Ahoj,
implementacia v Jave nepredpoklada, ze kodovanie nazvov suborov je v
cp852 (co v nasom regione je), takze to shavaruje. Musis si spravit
vlastne ZipInputStream a ZipOutputStream (+nejake dalsie aby to cele
fungovalo) podla zdrojakov a tie upravit tak, aby:
fileName = new String(b, 0, len, "Cp852");
Radovana Straube wrote / napísal(a):
Dobry den,
ked zipujem subory (pouzivam standarny java.util.zip a
JDK 1.5), ktore maju v nazvoch diakritiku, vo
vyslednom zip-e su nazvy suborov v zlom kodovani.
Nic rozumneho som nevygooglila. Riesil uz niekto
podobny problem?
Dakujem
Radovana Straube
P.S. Pripajam aj metodu, ktorou pouzivam na zipovanie
/**
* Compress a directory
* @param _sSourceDir a source directory
* @return a path to an archive
*/
private String compressDir(String _sSourceDir)
throws IOException {
// These are the files to include in the ZIP file
String[] sFilenames = new File(_sSourceDir).list();
// Create a buffer for reading the files
byte[] byBuf = new byte[1024];
// Create the ZIP file
String sZipArchive = extractArchiveName(_sSourceDir);
ZipOutputStream out = new ZipOutputStream(new
FileOutputStream(sZipArchive));
// Compress the files
for (int i = 0; i < sFilenames.length; i++) {
FileInputStream in = new
FileInputStream(_sSourceDir + sFilenames[i]);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(sFilenames[i]));
// Transfer bytes from the file to the ZIP file
int iLen;
while ((iLen = in.read(byBuf)) > 0) {
out.write(byBuf, 0, iLen);
}
// Complete the entry
out.closeEntry();
in.close();
}
// Complete the ZIP file
out.close();
return sZipArchive;
}
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