> Then what do you have after you remove the TCP headers at your
> destination? NOTHING? Just because a protocol doesn't know the
> internals of another protocol doesn't mean it would do anything about
> it.

You seem to think headers are the only things in packets.  After you
remove a header you still have the payload.

> BTW encapsulation and naive protocols are quite passe.

Tell that to all OOP programmers in the world.  They are all
striving for encapsulation by using objects.

> The most
> optimized performance comes from smart implementations that break just
> that rule.

I agree 100%.  Sure you can *implement* something with optimizations
that break encapsulation
but the TCP/IP specs strive for simplicity with encapsulation.

Chris


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