I've been having fun, playing with regular expressions in vi. But I'd
like to do more.
How can I do a search that regards line breaks as if they were a space?
If that's not easy, then how can I replace all line breaks with a space
except for line breaks or double line breaks preceding any line that
begins with "^"?
I have a text file that has been line wrapped at about 80 characters.
Each real line begins with the "^". Each wrapped line does not. And
each line that begins with "^" is preceded by a blank line.
Text that I want to search for (or replace) can wrap around these line
breaks, but not around the "^".
Example:
^1 This is a line
that is broken by
the super-imposed
word wrapping.
^2 Short line.
^3 Another line.
^4 Yet another.
^5 Some lines:
they wrap; Some
lines: they don't.
If I want to search the file for "line that is" and replace it with
"line which is", I would do ":%s/line that is/line which is/cg". But
this would totally miss the only occurrence of it in my example above.
If I could get vi to regard line breaks (during a search or replace) as
if they were a space, I'd be set.
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