On Tue, Jan 15, 2008 at 04:09:02PM -0800, Mark Schoonover wrote:
p = (int*) 42;
my $p = \42;
Um, no, that creates a box with a 42 in it, and stores a reference to the
42 in $p. The C code sets the pointer to 42. You can't have a Perl
reference that doesn't point to a real Perl object, at least not without
calling out to C.
In perl
print $$p, "\n";
prints 42. The C code.
printf ("%d\n", *p);
SEGFAULTs. Very different.
Dave
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