(There is an HTML version at <http://canonical.org/~kragen/strlen-utf8.html>.)

On IRC, [Aristotle Pagaltzis](http://plasmasturm.org) was pondering
how much performance variable-width encodings such as UTF-8 actually
cost, because it's commonly suggested that fixed-width encodings such
as ISO-8859-1 and UCS-4 are much faster.

He suggested:

> Huh, it just occurs to me that `strlen` is not at all expensive on
> UTF-8-encoded strings.  Not exactly as fast, but if you write it
> in asm, it only takes one extra instruction to count characters in
> UTF-8 vs those in an 8-bit encoding, per character. So, if you
> factor in cache misses, it should make no measurable
> difference. All you lose with a variable-width encoding is direct
> random access to arbitrary indices in the string, which is
> basically a non-use case.

It turned out that he was partly wrong, but mostly right.  And along
the way, we discovered that GCC's standard implementation of `strlen`
was quite pessimal.

I'm using Linux on a 700MHz Pentium III laptop with GCC 4.1.2, using
just the `-O` flag unless otherwise specified.

My First Assembly Version
-------------------------

First I thought about how to write `strlen`, and came up with this:

            .global my_strlen_s
    my_strlen_s:
            push %esi                
            cld
            mov 8(%esp), %esi
            xor %ecx, %ecx
            ## repnz lodsb doesn't work because lodsb doesn't update ZF
    loop:   lodsb
            test %al, %al
            loopnz loop
            mov %ecx, %eax
            not %eax
            pop %esi
            ret

> For those who aren't well-versed in 80386 assembly language:
> 
> - `lodsb` reads a byte from memory at `%esi`, puts it in `%al`, and
>   increments `%esi`;
> - `loopnz` decrements `%ecx` each time through the loop, and jumps
>   back to the label `loop:` if `%ecx` isn't zero and if the zero
>   flag `ZF` isn't set (that's the "nz" part);
> - `test %al, %al` sets the zero flag `ZF` if `%al` is zero (the C
>   string terminator), among other things.
> - after the loop body has run N times, `%ecx` is -N, so `not %eax`
>   converts the negative number -N from `%ecx` into a positive number
>   N-1.
> - you have to push `%esi` because it's a callee-saves register.  (To
>   my surprise.)
> 
> But there's a `scasb` instruction which I should have used instead
> of `lodsb; test`.

The inner loop there is three instructions.  

GCC's Assembly Version
----------------------

Then I looked at how GCC does `strlen`.  It turns out it inlines it,
even without any extra optimization flags.  Here's a sample call,
albeit with optimization:

     80484d5:   bf 00 99 04 08          mov    $0x8049900,%edi
     80484da:   fc                      cld    
     80484db:   b9 ff ff ff ff          mov    $0xffffffff,%ecx
     80484e0:   b0 00                   mov    $0x0,%al
     80484e2:   f2 ae                   repnz scas %es:(%edi),%al
     80484e4:   f7 d1                   not    %ecx
     80484e6:   49                      dec    %ecx
     80484e7:   89 4c 24 04             mov    %ecx,0x4(%esp)

There the inner loop is just the `repnz scas`.  I'd forgotten about
`SCAS`.

A C Version
-----------

Here's a reasonable `strlen` in C:

    int my_strlen(char *s) {
      int i = 0;
      while (*s++) i++;
      return i;
    }

This compiles to the following:

    080483c4 <my_strlen>:
     80483c4:   55                      push   %ebp
     80483c5:   89 e5                   mov    %esp,%ebp
     80483c7:   8b 55 08                mov    0x8(%ebp),%edx
     80483ca:   b8 00 00 00 00          mov    $0x0,%eax
     80483cf:   80 3a 00                cmpb   $0x0,(%edx)
     80483d2:   74 0c                   je     80483e0 <my_strlen+0x1c>
     80483d4:   b8 00 00 00 00          mov    $0x0,%eax
     80483d9:   40                      inc    %eax
     80483da:   80 3c 10 00             cmpb   $0x0,(%eax,%edx,1)
     80483de:   75 f9                   jne    80483d9 <my_strlen+0x15>
     80483e0:   5d                      pop    %ebp
     80483e1:   c3                      ret    

So here the inner loop is again three instructions: `inc %eax`; `cmpb
0, (%eax,%edx,1)`; `jne`.  It's been optimized down to `while (s[i])
i++;`.  The loop termination test is duplicated above the top of the
loop for the empty-string case.

My UTF-8 Assembly Version
-------------------------

So then I thought about how to do what Aristotle was suggesting.  In
UTF-8, bytes that start new characters begin either with binary 0 or
binary 11; the second and subsequent bytes of multibyte characters
have binary 10 as their high bits.  So to count the characters, you
just have to count the bytes that don't begin with binary 10.

I tried this:

            .global my_strlen_utf8_s
    my_strlen_utf8_s:
            push %esi
            cld
            mov 8(%esp), %esi
            xor %ecx, %ecx
    loop2:  lodsb
            test $0x80, %al
            jz ascii                # format 0xxx xxxx
            test $0x40, %al
            jz loop2                # format 10xx xxxx: doesn't start new char
    ascii:  test %al, %al
            loopnz loop2
            mov %ecx, %eax
            not %eax
            pop %esi
            ret

So here we jump back to `loop2`, rather than decrementing `%ecx` with
`loopnz`, in the case where the byte starts with 10.  And we can skip
the `test %al, %al` test, since 0000 0000 doesn't start with 10.

The inner loop of this version has 5 instructions, including two taken
conditional branches, in the usual ASCII case, and 7 instructions for
non-ASCII bytes, rather than 3 instructions per byte.  That's only two
extra instructions in the "usual" case, but if every instruction were
one cycle, that would still be a 67% increase in run-time.

Counting instructions and adding up their cycle count isn't a very
accurate way to measure performance in these superscalar days, though.

My UTF-8 C Version
------------------

A C version looks like this:

    int my_strlen_utf8_c(char *s) {
      int i = 0, j = 0;
      while (s[i]) {
        if ((s[i] & 0xc0) != 0x80) j++;
        i++;
      }
      return j;
    }

GCC compiles it to this:

    080483e2 <my_strlen_utf8_c>:
     80483e2:   55                      push   %ebp
     80483e3:   89 e5                   mov    %esp,%ebp
     80483e5:   8b 55 08                mov    0x8(%ebp),%edx
     80483e8:   0f b6 02                movzbl (%edx),%eax
     80483eb:   b9 00 00 00 00          mov    $0x0,%ecx
     80483f0:   84 c0                   test   %al,%al
     80483f2:   74 23                   je     8048417 <my_strlen_utf8_c+0x35>
     80483f4:   b9 00 00 00 00          mov    $0x0,%ecx
     80483f9:   0f be c0                movsbl %al,%eax
     80483fc:   25 c0 00 00 00          and    $0xc0,%eax
     8048401:   3d 80 00 00 00          cmp    $0x80,%eax
     8048406:   0f 95 c0                setne  %al
     8048409:   0f b6 c0                movzbl %al,%eax
     804840c:   01 c1                   add    %eax,%ecx
     804840e:   0f b6 42 01             movzbl 0x1(%edx),%eax
     8048412:   42                      inc    %edx
     8048413:   84 c0                   test   %al,%al
     8048415:   75 e2                   jne    80483f9 <my_strlen_utf8_c+0x17>
     8048417:   89 c8                   mov    %ecx,%eax
     8048419:   5d                      pop    %ebp
     804841a:   c3                      ret    

An inner loop of 10 instructions --- but containing only a single
conditional jump, the `jne` at the bottom.  It uses the `and`; `cmp`;
`setne`; `movzbl` sequence to put either a 0 or a 1 into `%eax`,
depending on whether the byte fetched began with 10, and adds the
result into `%ecx` each time through the loop.

Aristotle's UTF-8 Assembly Version
----------------------------------

So after all this, I chatted with Aristotle some more, and it turned
out he had a much cleverer trick up his sleeve than I had thought ---
or, in fact, than he had thought.  He wrote:

> But wow, my code is *much* faster than any of the other variants.
> Unexpectedly.

Here's his version:

            .global ap_strlen_utf8_s
    ap_strlen_utf8_s:
            push %esi
            cld
            mov 8(%esp), %esi
            xor %ecx, %ecx
    loopa:  dec %ecx
    loopb:  lodsb
            shl $1, %al
            js loopa
            jc loopb
            jnz loopa
            mov %ecx, %eax
            not %eax
            pop %esi
            ret

In this case, the inner loop is 6 instructions, but as few as 3 of
them can execute.  I hadn't realized that you could get the top two
bits of a byte into the carry and sign flags with a single `shl`
instruction like that!  Aristotle explains:

> `Js` catches all bytes of the form x1xxxxxx. `Jc` catches 1xxxxxxx,
> but because `js` came first, that can only have been 10xxxxxx; and
> `jnz` then catches all 00xxxxxx other than all-0.  This runs about
> 3x as fast as your `my_strlen_s` --- most of the time, anyway.

Performance Results
-------------------

So how do these different approaches fare?  I wrote a program that
creates a 32MB string and timed the different functions on it, in
seconds, using wall-clock time.  Here are the results from one run,
sorted with `sort -t: -k1 -k3 -ns`.  The first few lines are various
functions' return values on the given strings.

    "": 0 0 0 0 0 0
    "hello, world": 12 12 12 12 12 12
    "naïve": 6 6 6 5 5 5
    "こんにちは": 15 15 15 5 5 5
    1: all 'a':
    1:                my_strlen(string) =   33554431: 0.227555
    1:         ap_strlen_utf8_s(string) =   33554431: 0.299494
    1:                   strlen(string) =   33554431: 0.314887
    1:         my_strlen_utf8_c(string) =   33554431: 0.380355
    1:              my_strlen_s(string) =   33554431: 0.432079
    1:         my_strlen_utf8_s(string) =   33554431: 0.525443
    2: all '\xe3':
    2:                my_strlen(string) =   33554431: 0.224037
    2:         ap_strlen_utf8_s(string) =   33554431: 0.299537
    2:                   strlen(string) =   33554431: 0.311552
    2:         my_strlen_utf8_c(string) =   33554431: 0.378162
    2:              my_strlen_s(string) =   33554431: 0.436755
    2:         my_strlen_utf8_s(string) =   33554431: 0.589165
    3: all '\x81':
    3:                my_strlen(string) =   33554431: 0.225011
    3:         ap_strlen_utf8_s(string) =          0: 0.313525
    3:                   strlen(string) =   33554431: 0.316182
    3:         my_strlen_utf8_s(string) =          0: 0.322959
    3:         my_strlen_utf8_c(string) =          0: 0.390958
    3:              my_strlen_s(string) =   33554431: 0.432342

The 33554431 and 0 numbers are the return values; this ensures that
GCC doesn't optimize out the `strlen` call.

So, on my CPU, the C version of `strlen` took about 28% less time than
the built-in inlined one for this long string; it only uses two
registers instead of the three used by the built-in inlined one (the
one that uses `repnz scasb`); and they both seem to be about 12 bytes.
I don't know why GCC inlines the worse one. Most likely it used to be
faster than whatever GCC generated at the time and hasn't been
revisited.

It's worth noting that while my C version of `strlen` was always
faster than the built-in version, Aristotle's UTF-8 version was always
in between.

On Aristotle's Core 2 Duo 1.8GHz (also with GCC 4.1.2 and `-O`), the
difference was very much greater.  Here are his results:

    "": 0 0 0 0 0 0
    "hello, world": 12 12 12 12 12 12
    "naïve": 6 6 6 5 5 5
    "こんにちは": 15 15 15 5 5 5
    1: all 'a':
    1:                my_strlen(string) =   33554431: 0.025906
    1:         ap_strlen_utf8_s(string) =   33554431: 0.039629
    1:         my_strlen_utf8_c(string) =   33554431: 0.096041
    1:                   strlen(string) =   33554431: 0.114821
    1:              my_strlen_s(string) =   33554431: 0.116529
    1:         my_strlen_utf8_s(string) =   33554431: 0.132648
    2: all '\xe3':
    2:                my_strlen(string) =   33554431: 0.025912
    2:         ap_strlen_utf8_s(string) =   33554431: 0.039583
    2:         my_strlen_utf8_c(string) =   33554431: 0.095699
    2:                   strlen(string) =   33554431: 0.114452
    2:              my_strlen_s(string) =   33554431: 0.114622
    2:         my_strlen_utf8_s(string) =   33554431: 0.136109
    3: all '\x81':
    3:                my_strlen(string) =   33554431: 0.026112
    3:         my_strlen_utf8_s(string) =          0: 0.039656
    3:         ap_strlen_utf8_s(string) =          0: 0.039661
    3:         my_strlen_utf8_c(string) =          0: 0.096416
    3:              my_strlen_s(string) =   33554431: 0.115327
    3:                   strlen(string) =   33554431: 0.116629

All of this code is online in two files:

* [mystrlen.c](http://pobox.com/~kragen/sw/mystrlen.c)
* [mystrlen.s](http://pobox.com/~kragen/sw/mystrlen.s)

Conclusions
-----------

1. GCC is better at writing x86 assembly than I am.  No surprise
   there.  Even when its inner loop is 10 instructions, it beats my
   three-instruction inner loops for speed.

2. Aristotle is better at writing x86 assembly than GCC is.

3. Aristotle was essentially correct: the penalty for counting UTF-8
   characters, or indexing into or iterating over the characters of a
   UTF-8 string, is very small.

4. However, there is a speed penalty.  Although GCC's built-in
   `strlen` is much slower than Aristotle's function, a
   straightforward byte-counting C `strlen` compiled with optimization
   is faster still.

5. GCC should change to use the straightforward byte-counting C
   `strlen` instead of what it currently inlines.  The version of
   strlen that GCC inlines is worse than the one it compiled from C in
   every way: it's more instructions, more bytes of machine code, four
   times slower, and uses more registers (one of which is a
   callee-saves register!).

6. People probably shouldn't worry about the efficiency of counting
   and iterating over characters in UTF-8 strings, at least not if
   they were using null-terminated C strings before.

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