On 04/08/15 15:32, Christoffer Dall wrote:
> On Fri, Jul 24, 2015 at 04:55:09PM +0100, Marc Zyngier wrote:
>> So far, the only use of the HW interrupt facility is the timer,
>> implying that the active state is context-switched for each vcpu,
>> as the device is is shared across all vcpus.
>>
>> This does not work for a device that has been assigned to a VM,
>> as the guest is entierely in control of that device (the HW is
>> not shared). In that case, it makes sense to bypass the whole
>> active state switching, and only track the deactivation of the
>> interrupt.
>>
>> Signed-off-by: Marc Zyngier <[email protected]>
>> ---
>>  include/kvm/arm_vgic.h    |  6 ++--
>>  virt/kvm/arm/arch_timer.c |  3 +-
>>  virt/kvm/arm/vgic.c       | 73 
>> +++++++++++++++++++++++++++++++++++++----------
>>  3 files changed, 64 insertions(+), 18 deletions(-)
>>
>> diff --git a/include/kvm/arm_vgic.h b/include/kvm/arm_vgic.h
>> index f6bfd79..6f0a4e1 100644
>> --- a/include/kvm/arm_vgic.h
>> +++ b/include/kvm/arm_vgic.h
>> @@ -164,7 +164,8 @@ struct irq_phys_map {
>>      u32                     phys_irq;
>>      u32                     irq;
>>      bool                    deleted;
>> -    bool                    active;
>> +    bool                    shared;
>> +    bool                    active; /* Only valid if shared */
>>  };
>>  
>>  struct irq_phys_map_entry {
>> @@ -357,7 +358,8 @@ void vgic_v3_dispatch_sgi(struct kvm_vcpu *vcpu, u64 
>> reg);
>>  int kvm_vgic_vcpu_pending_irq(struct kvm_vcpu *vcpu);
>>  int kvm_vgic_vcpu_active_irq(struct kvm_vcpu *vcpu);
>>  struct irq_phys_map *kvm_vgic_map_phys_irq(struct kvm_vcpu *vcpu,
>> -                                       int virt_irq, int irq);
>> +                                       int virt_irq, int irq,
>> +                                       bool shared);
>>  int kvm_vgic_unmap_phys_irq(struct kvm_vcpu *vcpu, struct irq_phys_map 
>> *map);
>>  bool kvm_vgic_get_phys_irq_active(struct irq_phys_map *map);
>>  void kvm_vgic_set_phys_irq_active(struct irq_phys_map *map, bool active);
>> diff --git a/virt/kvm/arm/arch_timer.c b/virt/kvm/arm/arch_timer.c
>> index 76e38d2..db21d8f 100644
>> --- a/virt/kvm/arm/arch_timer.c
>> +++ b/virt/kvm/arm/arch_timer.c
>> @@ -203,7 +203,8 @@ int kvm_timer_vcpu_reset(struct kvm_vcpu *vcpu,
>>       * Tell the VGIC that the virtual interrupt is tied to a
>>       * physical interrupt. We do that once per VCPU.
>>       */
>> -    map = kvm_vgic_map_phys_irq(vcpu, irq->irq, host_vtimer_irq);
>> +    map = kvm_vgic_map_phys_irq(vcpu, irq->irq,
>> +                                host_vtimer_irq, true);
>>      if (WARN_ON(IS_ERR(map)))
>>              return PTR_ERR(map);
>>  
>> diff --git a/virt/kvm/arm/vgic.c b/virt/kvm/arm/vgic.c
>> index e40ef70..5e6b816 100644
>> --- a/virt/kvm/arm/vgic.c
>> +++ b/virt/kvm/arm/vgic.c
>> @@ -1128,19 +1128,25 @@ static void vgic_queue_irq_to_lr(struct kvm_vcpu 
>> *vcpu, int irq,
>>               * active in the physical world. Otherwise the
>>               * physical interrupt will fire and the guest will
>>               * exit before processing the virtual interrupt.
>> +             *
>> +             * This is of course only valid for a shared
>> +             * interrupt. A non shared interrupt should already be
>> +             * active.
>>               */
>>              if (map) {
>> -                    int ret;
>> -
>> -                    BUG_ON(!map->active);
>>                      vlr.hwirq = map->phys_irq;
>>                      vlr.state |= LR_HW;
>>                      vlr.state &= ~LR_EOI_INT;
>>  
>> -                    ret = irq_set_irqchip_state(map->irq,
>> -                                                IRQCHIP_STATE_ACTIVE,
>> -                                                true);
>> -                    WARN_ON(ret);
>> +                    if (map->shared) {
>> +                            int ret;
>> +
>> +                            BUG_ON(!map->active);
>> +                            ret = irq_set_irqchip_state(map->irq,
>> +                                                        
>> IRQCHIP_STATE_ACTIVE,
>> +                                                        true);
>> +                            WARN_ON(ret);
>> +                    }
>>  
>>                      /*
>>                       * Make sure we're not going to sample this
>> @@ -1383,21 +1389,41 @@ static bool vgic_process_maintenance(struct kvm_vcpu 
>> *vcpu)
>>  static int vgic_sync_hwirq(struct kvm_vcpu *vcpu, struct vgic_lr vlr)
>>  {
>>      struct irq_phys_map *map;
>> +    bool active;
>>      int ret;
>>  
>>      if (!(vlr.state & LR_HW))
>>              return 0;
>>  
>>      map = vgic_irq_map_search(vcpu, vlr.irq);
>> -    BUG_ON(!map || !map->active);
>> +    BUG_ON(!map);
>> +    BUG_ON(map->shared && !map->active);
>>  
>>      ret = irq_get_irqchip_state(map->irq,
>>                                  IRQCHIP_STATE_ACTIVE,
>> -                                &map->active);
>> +                                &active);
>>  
>>      WARN_ON(ret);
>>  
>> -    if (map->active) {
>> +    /*
>> +     * For a non-shared interrupt, we have to cater for two
>> +     * possible deactivation conditions:
>> +     *
>> +     * - the physical interrupt is now inactive (EOIed from the
>> +         *   guest)
> 
> nit: whitespace funkyness
> 
>> +     * - the physical interrupt is still active, but its virtual
>> +     *   counterpart is flagged as "not queued", indicating another
>> +     *   interrupt has fired between the EOI and the guest exit.
>> +     *
>> +     * Also, we are not reactivating a non-shared interrupt
> 
> what does reactivating mean? did you mean deactivate?

Deactivate indeed.

>> +     * ourselves. This is always left to the guest.
> 
> In which case, add ", because the device is solely owned by the guest."

Sure.

>> +     */
>> +    if (!map->shared)
>> +            return !active || !vgic_irq_is_queued(vcpu, vlr.irq);
> 
> do you really need the second part of the disjunction?
> 
> The effect seems to be that we clear the queued flag once again, and
> clear the LR.  If we don't do this, won't we simply pick up the pending
> flag next time we're about to run this VCPU and piggy-back on the
> existing LR.  Perhaps this is a weird flow though?

Crucially, we free the LR in this case (the set_bit on elrsr_ptr). If we
don't do this, we're indeed going to schedule the vcpu (it has something
to process), but we never allow piggy-backing on level interrupts. We'd
need some special hack to handle this.

I definitely feel more comfortable reporting that the interrupt has been
deactivated (which is the case), and let the normal flow pick up the
next injected interrupt.

> 
>> +
>> +    map->active = active;
>> +
>> +    if (active) {
>>              ret = irq_set_irqchip_state(map->irq,
>>                                          IRQCHIP_STATE_ACTIVE,
>>                                          false);
>> @@ -1590,6 +1616,17 @@ static int vgic_update_irq_pending(struct kvm *kvm, 
>> int cpuid,
>>              goto out;
>>      }
>>  
>> +    if (map && !map->shared) {
>> +            /*
>> +             * We are told to inject a HW irq, so we have to trust
>> +             * the caller that the previous one has been EOIed,
>> +             * and that a new one is now active. Clearing the
>> +             * queued state will have the effect of making it
>> +             * sample-able again.
>> +             */
>> +            vgic_irq_clear_queued(vcpu, irq_num);
>> +    }
>> +
>>      if (!vgic_can_sample_irq(vcpu, irq_num)) {
>>              /*
>>               * Level interrupt in progress, will be picked up
>> @@ -1720,15 +1757,19 @@ static struct list_head 
>> *vgic_get_irq_phys_map_list(struct kvm_vcpu *vcpu,
>>   * @vcpu: The VCPU pointer
>>   * @virt_irq: The virtual irq number
>>   * @irq: The Linux IRQ number
>> + * @shared: Indicates if the interrupt has to be context-switched or
>> + *          if it is private to a VM
>>   *
>>   * Establish a mapping between a guest visible irq (@virt_irq) and a
>>   * Linux irq (@irq). On injection, @virt_irq will be associated with
>> - * the physical interrupt represented by @irq.
>> + * the physical interrupt represented by @irq. If @shared is true,
>> + * the active state of the interrupt will be context-switched.
>>   *
>>   * Returns a valid pointer on success, and an error pointer otherwise
>>   */
>>  struct irq_phys_map *kvm_vgic_map_phys_irq(struct kvm_vcpu *vcpu,
>> -                                       int virt_irq, int irq)
>> +                                       int virt_irq, int irq,
>> +                                       bool shared)
>>  {
>>      struct vgic_dist *dist = &vcpu->kvm->arch.vgic;
>>      struct list_head *root = vgic_get_irq_phys_map_list(vcpu, virt_irq);
>> @@ -1762,7 +1803,8 @@ struct irq_phys_map *kvm_vgic_map_phys_irq(struct 
>> kvm_vcpu *vcpu,
>>      if (map) {
>>              /* Make sure this mapping matches */
>>              if (map->phys_irq != phys_irq   ||
>> -                map->irq      != irq)
>> +                map->irq      != irq        ||
>> +                map->shared   != shared)
>>                      map = ERR_PTR(-EINVAL);
>>  
>>              goto out;
>> @@ -1772,6 +1814,7 @@ struct irq_phys_map *kvm_vgic_map_phys_irq(struct 
>> kvm_vcpu *vcpu,
>>      map->virt_irq = virt_irq;
>>      map->phys_irq = phys_irq;
>>      map->irq      = irq;
>> +    map->shared   = shared;
>>  
>>      list_add_tail_rcu(&entry->entry, root);
>>  
>> @@ -1822,7 +1865,7 @@ static void vgic_free_phys_irq_map_rcu(struct rcu_head 
>> *rcu)
>>   */
>>  bool kvm_vgic_get_phys_irq_active(struct irq_phys_map *map)
>>  {
>> -    BUG_ON(!map);
>> +    BUG_ON(!map || !map->shared);
>>      return map->active;
>>  }
>>  
>> @@ -1834,7 +1877,7 @@ bool kvm_vgic_get_phys_irq_active(struct irq_phys_map 
>> *map)
>>   */
>>  void kvm_vgic_set_phys_irq_active(struct irq_phys_map *map, bool active)
>>  {
>> -    BUG_ON(!map);
>> +    BUG_ON(!map || !map->shared);
>>      map->active = active;
>>  }
>>  
>> -- 
>> 2.1.4
>>
> 
> I think I'm seeing this in the correct light this time around, so this
> is functionally looking pretty good to me.
> 
> Thanks,
> -Christoffer
> 

Thanks,

        M.
-- 
Jazz is not dead. It just smells funny...
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