On Tue, Jul 07, 2009 at 09:58:46AM +0000, Eran Rom wrote:
> Eran Rom <eranr <at> il.ibm.com> writes:
>
> >
> > Eran Rom <eranr <at> il.ibm.com> writes:
> >
> > Still getting a misbehaving clock:
> > guest uses kvmclock with kernel 2.6.27
> > host kernel is 2.6.27 with kvm-qemu-87 & kvm-kmod-87
> >
> > getting:
> > ...
> > now = 2128043797
> > now = 2138048010
> > now = 18446744071562636328
> >
Eran,
This was happening with kvmclock back then when it did not handle
cpu frequency changes. What are the details of the host hw?
Glauber, any clues?
> Below is the exact code used.
> Also, I use a script in the host to run this code in a loop for 5 minutes,
> each
> time in a newly launched guest. This happens on average once every 10
> executions.
>
> Thanks very much,
> Eran
>
> #include <sys/time.h>
> #include <time.h>
>
> int main(int argc, char **argv)
> {
> int seconds;
> unsigned long long now, goal;
> struct timeval time1, time2;
>
> if (argc != 2)
> return;
>
> seconds = atoi(argv[1]);
>
> gettimeofday(&time1, NULL);
> now = ((time1.tv_sec) * 1000000) + time1.tv_usec;
> goal = now + (seconds * 1000000);
> while (now < goal) {
> sleep(10);
> gettimeofday(&time2, NULL);
> now = (time2.tv_sec * 1000000) + time2.tv_usec;
> }
> }
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