On 01/10/2011 09:31 AM, Jan Kiszka wrote:
From: Jan Kiszka<[email protected]>
We do not use the timeout, so drop its logic. As we always poll our
signals, we do not need to drop the global lock. Removing those calls
allows some further simplifications. Also fix the error processing of
sigpending at this chance.
Signed-off-by: Jan Kiszka<[email protected]>
---
cpus.c | 23 +++++++----------------
1 files changed, 7 insertions(+), 16 deletions(-)
diff --git a/cpus.c b/cpus.c
index bf0fb85..6da0f8f 100644
--- a/cpus.c
+++ b/cpus.c
@@ -617,31 +617,22 @@ static void sigbus_handler(int n, struct
qemu_signalfd_siginfo *siginfo,
}
}
-static void qemu_kvm_eat_signal(CPUState *env, int timeout)
+static void qemu_kvm_eat_signals(CPUState *env)
{
- struct timespec ts;
- int r, e;
+ struct timespec ts = { 0, 0 };
siginfo_t siginfo;
sigset_t waitset;
sigset_t chkset;
-
- ts.tv_sec = timeout / 1000;
- ts.tv_nsec = (timeout % 1000) * 1000000;
+ int r;
sigemptyset(&waitset);
sigaddset(&waitset, SIG_IPI);
sigaddset(&waitset, SIGBUS);
do {
- qemu_mutex_unlock(&qemu_global_mutex);
-
r = sigtimedwait(&waitset,&siginfo,&ts);
- e = errno;
-
- qemu_mutex_lock(&qemu_global_mutex);
-
- if (r == -1&& !(e == EAGAIN || e == EINTR)) {
- fprintf(stderr, "sigtimedwait: %s\n", strerror(e));
+ if (r == -1&& !(errno == EAGAIN || errno == EINTR)) {
+ perror("sigtimedwait");
exit(1);
}
@@ -657,7 +648,7 @@ static void qemu_kvm_eat_signal(CPUState *env, int timeout)
r = sigpending(&chkset);
if (r == -1) {
- fprintf(stderr, "sigpending: %s\n", strerror(e));
+ perror("sigpending");
exit(1);
}
} while (sigismember(&chkset, SIG_IPI) || sigismember(&chkset, SIGBUS));
@@ -668,7 +659,7 @@ static void qemu_kvm_wait_io_event(CPUState *env)
while (!cpu_has_work(env))
qemu_cond_timedwait(env->halt_cond,&qemu_global_mutex, 1000);
- qemu_kvm_eat_signal(env, 0);
+ qemu_kvm_eat_signals(env);
qemu_wait_io_event_common(env);
}
Reviewed-by: Paolo Bonzini <[email protected]>
Paolo
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