On 2013-08-06 17:04, Zhang, Yang Z wrote:
> Gleb Natapov wrote on 2013-08-06:
>> On Tue, Aug 06, 2013 at 02:12:51PM +0000, Zhang, Yang Z wrote:
>>> Gleb Natapov wrote on 2013-08-06:
>>>> On Tue, Aug 06, 2013 at 11:44:41AM +0000, Zhang, Yang Z wrote:
>>>>> Gleb Natapov wrote on 2013-08-06:
>>>>>> On Tue, Aug 06, 2013 at 10:39:59AM +0200, Jan Kiszka wrote:
>>>>>>> From: Jan Kiszka <[email protected]>
>>>>>>>
>>>>>>> If nested EPT is enabled, the L2 guest may change CR3 without any
>>>>>>> exits. We therefore have to read the current value from the VMCS
>>>>>>> when switching to L1. However, if paging wasn't enabled, L0 tracks
>>>>>>> L2's CR3, and GUEST_CR3 rather contains the real-mode identity map.
>>>>>>> So we need to retrieve CR3 from the architectural state after
>>>>>>> conditionally updating it - and this is what kvm_read_cr3 does.
>>>>>>>
>>>>>> I have a headache from trying to think about it already, but
>>>>>> shouldn't
>>>>>> L1 be the one who setups identity map for L2? I traced what
>>>>>> vmcs_read64(GUEST_CR3)/kvm_read_cr3(vcpu) return here and do not
>>>>>> see
>>>>> Here is my understanding:
>>>>> In vmx_set_cr3(), if enabled ept, it will check whether target
>>>>> vcpu is enabling
>>>> paging. When L2 running in real mode, then target vcpu is not
>>>> enabling paging and it will use L0's identity map for L2. If you
>>>> read GUEST_CR3 from VMCS, then you may get the L2's identity map
>>>> not
>> L1's.
>>>>>
>>>> Yes, but why it makes sense to use L0 identity map for L2? I didn't
>>>> see different vmcs_read64(GUEST_CR3)/kvm_read_cr3(vcpu) values because
>>>> L0 and L1 use the same identity map address. When I changed identity
>>>> address L1 configures vmcs_read64(GUEST_CR3)/kvm_read_cr3(vcpu) are
>>>> indeed different, but the real CR3 L2 uses points to L0 identity map.
>>>> If I zero L1 identity map page L2 still works.
>>>>
>>> If L2 in real mode, then L2PA == L1PA. So L0's identity map also works
>>> if L2 is in real mode.
>>>
>> That not the point. It may work accidentally for kvm on kvm, but what
>> if other hypervisor plays different tricks and builds different ident map
>> for its guest?
> Yes, if other hypervisor doesn't build the 1:1 mapping for its guest, it will
> fail to work. But I cannot imagine what kind of hypervisor will do this and
> what the purpose is.
> Anyway, current logic is definitely wrong. It should use L1's identity map
> instead L0's.
So something like this is rather needed?
diff --git a/arch/x86/kvm/vmx.c b/arch/x86/kvm/vmx.c
index 44494ed..60a3644 100644
--- a/arch/x86/kvm/vmx.c
+++ b/arch/x86/kvm/vmx.c
@@ -3375,8 +3375,10 @@ static void vmx_set_cr3(struct kvm_vcpu *vcpu, unsigned
long cr3)
if (enable_ept) {
eptp = construct_eptp(cr3);
vmcs_write64(EPT_POINTER, eptp);
- guest_cr3 = is_paging(vcpu) ? kvm_read_cr3(vcpu) :
- vcpu->kvm->arch.ept_identity_map_addr;
+ if (is_paging(vcpu) || is_guest_mode(vcpu))
+ guest_cr3 = kvm_read_cr3(vcpu) :
+ else
+ guest_cr3 = vcpu->kvm->arch.ept_identity_map_addr;
ept_load_pdptrs(vcpu);
}
Jan
--
Siemens AG, Corporate Technology, CT RTC ITP SES-DE
Corporate Competence Center Embedded Linux
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