Can I just do 1/2 m*v^2 = modes.velocities, assuming parabolic dispersion? On Mon, Jan 23, 2017 at 3:13 PM, Harshad Sahasrabudhe <hsaha...@purdue.edu> wrote:

> Hi, > > You could do that, but this is already done in Kwant, and you can read the >> velocities off from the modes object [1]. > > > I was able to obtain the velocities from the modes object. I confirmed > that modes.velocities is just the inverse of integral |𝜓|2 over the unit > cell. If I did the math correctly, I got the units of modes.velocities to > be eV (energy units of my Hamiltonian). How can I convert this to lets say > m/s? > > Thanks, > Harshad > > On Mon, Jan 23, 2017 at 10:18 AM, Harshad Sahasrabudhe < > hsaha...@purdue.edu> wrote: > >> Great, thanks a lot! >> >> On Mon, Jan 23, 2017 at 10:15 AM, Anton Akhmerov < >> anton.akhmerov...@gmail.com> wrote: >> >>> > Thank you. Then to calculate the velocity, should I just divide the >>> > probability current by the integral of |𝜓|2 over the unit cell? >>> >>> You could do that, but this is already done in Kwant, and you can read >>> the velocities off from the modes object [1]. >>> >>> Best, >>> Anton >>> >>> [1]: https://kwant-project.org/doc/1/reference/generated/kwant.ph >>> ysics.PropagatingModes#kwant.physics.PropagatingModes >>> >> >> >