I'm pretty old school, `tr` would be my utility of choice. But
according to my bash manual, trailing newlines are automatically
elided by the shell:
Command substitution allows the output of a command to replace the
com-
mand name. There are two forms:
$(command)
or
`command`
Bash performs the expansion by executing command and
replacing the com-
mand substitution with the standard output of the
command, with any
trailing newlines deleted. Embedded newlines are not
deleted, but they
may be removed during word splitting. The command
substitution $(cat
file) can be replaced by the equivalent but faster $(< file).
When the old-style backquote form of substitution is
used, backslash
retains its literal meaning except when followed by $, `,
or \. The
first backquote not preceded by a backslash terminates the
command sub-
stitution. When using the $(command) form, all characters
between the
parentheses make up the command; none are treated specially.
Command substitutions may be nested. To nest when using the
backquoted
form, escape the inner backquotes with backslashes.
If the substitution appears within double quotes, word
splitting and
pathname expansion are not performed on the results.
On 2007-05-30, at 12:20 EDT, Henry Minsky wrote:
I have a shell script which binds a variable to the output of a
program, and
there is a newline
at the end of it that I want to remove. What is the best way to do
this? Is
there a bash builtin
which handles that, or should I just run it through sed?
--
Henry Minsky
Software Architect
[EMAIL PROTECTED]
