But shouldn't it still work with parent.x+5 anyway?
Not quite. parent.x refers to the parent's x position relative to the
canvas. In your example, the first red view has an x of 0 in the canvas.
The interior view is constrained to have an x of parent.x + 5, which
works out to 5 in this case. The second red view has an x of 100
relative to the canvas. The interior view therefore has an x of 105.
Since it is being place 105 pixels from the left of the second red view,
the views are not working as desired. Here's a modified version:
<canvas width="600" height="400">
<simplelayout axis="x"/>
<view name="first"
bgcolor="red" width="100" height="100">
<view bgcolor="black"
width="${ parent.width - 10 }" height="${ parent.height -
10 }"
x="5" y="5"/>
</view>
<view name="second"
bgcolor="red" width="100" height="100">
<view bgcolor="black"
width="${ parent.width - 10 }" height="${ parent.height -
10 }"
x="5" y="5"/>
</view>
</canvas>
<canvas width="600" height="400">
<simplelayout axis="x"/>
<view bgcolor="red" width="100" height="100">
<view bgcolor="black"
width="${parent.width-10}"
height="${parent.height-10}"
x="${parent.x+5}"
y="${parent.y+5}"/>
</view>
<view bgcolor="red" width="100" height="100">
<view bgcolor="black"
width="${parent.width-10}"
height="${parent.height-10}"
x="${parent.x+5}"
y="${parent.y+5}"/>
</view>
</canvas>
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Dan Stowell
Software Engineer
Laszlo Studios
Dan Stowell
Software Engineer
Laszlo Studios
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