On Mon, 12 Apr 2010 19:11:17 Bjorn Tillenius wrote: > On Mon, Apr 12, 2010 at 08:01:24AM +0100, Graham Binns wrote: > > On 12 April 2010 06:04, Tim Penhey <[email protected]> wrote: > > > Hi Deryck, > > > > > > As discussed before I'm tackling the JFDI approach and I'm going to get > > > the scanner to update the bug-task status [1]. > > > > > > I'd like the bug-task to be set to in-progress when it is linked to the > > > branch, and fix-committed if it is linked to a branch that was marked > > > as merged through a merge proposal. > > > > > > Since the scanner is a script, what do you think the best approach is > > > so that the appropriate subscribers get notified? Â I had a brief look > > > at the bug code but it was not clear to me exactly how to proceed. > > > > The simplest way I can think of, though not a particularly elegant one, > > > > is to do something like this: > > from lp.bugs.adapters.bugchange import BugTaskStatusChange > > change = BugTaskStatusChange( > > > > bug_task=bug_task, when=UTC_NOW, person=current_person, > > what_changed='status', old_value=old_bugtask_status.title, > > new_value=new_bugtask_status.title) > > > > bug_task.bug.addChange(change) > > > > However, I'd be inclined to say "use whatever the API uses," but I don't > > actually know what that is (just from a bit of looking around at pre-8am > > I can't find it, anyway). > > The easiest way is probably to use IBug.setStatus(). It will do the > right thing (including notifying people about changes), even if you pass > in an IProductSeries.
Ah ha, but I don't have a person. Should I use a celebrity? Tim _______________________________________________ Mailing list: https://launchpad.net/~launchpad-dev Post to : [email protected] Unsubscribe : https://launchpad.net/~launchpad-dev More help : https://help.launchpad.net/ListHelp
