On Fri, 26 May 2017 11:47:35 +0100 Graeme Geldenhuys via Lazarus <[email protected]> wrote:
> Hi, > > Does CodeTools only know about the unit or units that are currently > open? Or does in know about all files in a project - and maybe even > associated packages? Codetools only knows about the defines for each directory. But any IDE addon can access source editor and codetools. > The problem > =========== > I want to implement a Lazarus IDE feature "open type" - that's if it > doesn't already exist (please let me know). Imagine, you need to have a > look at the "TFoo" class. But, where is the "TFoo" class? Is it in the > "Boo" project or maybe in the Boo_tools.lpk package? Or somewhere else > (in a project search path)? > > I would like to be able to simply trigger the "Open Type" shortcut, > which shows me a dialog where I can type "Foo", and a listbox below that > will list all possible class matches with the name "Foo" (similar to > what the Procedure List dialog currently does. I can then simply press > Enter to select the first found option, or press the up/down arrows to > select another match and then press Enter, and it will take me to the > correct unit and class definition. Sounds like cody's dictionary: http://wiki.lazarus.freepascal.org/Cody#Unit_.2F_Identifier_Dictionary > Ctrl+LClick can already to this - somewhat. But for Ctrl+LClick to work, > you need the correct unit in the uses clause. My problem is, what if you > don't know the unit name either, or the unit name isn't in the uses list > (yet - or might not even be needed at all, you simply wanted to double > check something in the "TFoo" class). Mattias -- _______________________________________________ Lazarus mailing list [email protected] http://lists.lazarus-ide.org/listinfo/lazarus
