On 09/03/13 12:11, Howard Page-Clark wrote:
On 09/03/13 11:12, appjaws wrote:
Hi all,
I have a series of results, for each day of the month I have 10 numbers
ranging from 1 to 20. i.e.
Day1 1,3,4,5,7,9,12,16,17,20
Day2 3,4,5,6,8,9,15,17,18,19
etc.
Question 1 how can I find the number of 1's 2's 3's 4's etc. for the
whole month series?
Question 2 How can I test for 3 or more consecutive numbers in each day?
Q1 for such a small dataset a brute force approach of iterating over all
values and counting each occurrence of 1, 2, 3 etc. in 20 distinct
counters seems best.
Q2 Your data is ordered by value, so a function along these lines ought
to work:
type
TNumber = 1..20;
TDayData = array[1..10] of TNumber;
function ThreeOrMoreConsecutiveNos(dd: TDayData): boolean;
var i: integer=1;
begin
Result:= False;
while i <=8 do
begin
if ( dd[i]=Pred(dd[i+1]) )
and ( dd[i+1]=Pred(dd[i+2]) )
then Exit(True);
Inc(i);
end;
end;
Thank you Howard,
I just realised that I need to sort the numbers because they are not
like my example above. So where and how would I sort the array for each
Day and then call ThreeOrMore?
I'm still learning and really appreciate your help
Paul
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