unsigned short pippo; 1) pippo = pippo & 0x00FF; 2) pippo &= 0x00FF; In line 2, no warning is pointed out, while in line 1 is pointed out a warning of assignment of int to unsinged int Why? Haven't them the same meaning? Best regards Ferrara Filippo
- Re: Operations with same meaning filippo . ferrara
- Re: Operations with same meaning David Dyck